Base | Representation |
---|---|
bin | 11000011101010101… |
… | …10011000100000001 |
3 | 1020220010022000120121 |
4 | 30032222303010001 |
5 | 203343014031423 |
6 | 10010550540241 |
7 | 643253450665 |
oct | 141652630401 |
9 | 36803260517 |
10 | 13131002113 |
11 | 5629121269 |
12 | 2665667681 |
13 | 131357b648 |
14 | 8c7d0a8a5 |
15 | 51cbcc45d |
hex | 30eab3101 |
13131002113 has 16 divisors (see below), whose sum is σ = 14358196944. Its totient is φ = 11958036480.
The previous prime is 13131002057. The next prime is 13131002117. The reversal of 13131002113 is 31120013131.
It can be written as a sum of positive squares in 8 ways, for example, as 529368064 + 12601634049 = 23008^2 + 112257^2 .
It is a cyclic number.
It is not a de Polignac number, because 13131002113 - 29 = 13131001601 is a prime.
It is a super-2 number, since 2×131310021132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13131002117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56181 + ... + 171517.
It is an arithmetic number, because the mean of its divisors is an integer number (897387309).
Almost surely, 213131002113 is an apocalyptic number.
It is an amenable number.
13131002113 is a deficient number, since it is larger than the sum of its proper divisors (1227194831).
13131002113 is a wasteful number, since it uses less digits than its factorization.
13131002113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115572.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 13131002113 its reverse (31120013131), we get a palindrome (44251015244).
The spelling of 13131002113 in words is "thirteen billion, one hundred thirty-one million, two thousand, one hundred thirteen".
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