Base | Representation |
---|---|
bin | 10011000110111010111… |
… | …110110000001100011011 |
3 | 11122112100100010221012221 |
4 | 103012322332300030123 |
5 | 133003213110202122 |
6 | 2443121501444511 |
7 | 163603615106311 |
oct | 23067276601433 |
9 | 4575310127187 |
10 | 1313102037787 |
11 | 4669799600a1 |
12 | 1925a3270737 |
13 | 96a95674317 |
14 | 477a96b60b1 |
15 | 242542d06c7 |
hex | 131bafb031b |
1313102037787 has 2 divisors, whose sum is σ = 1313102037788. Its totient is φ = 1313102037786.
The previous prime is 1313102037769. The next prime is 1313102037803. The reversal of 1313102037787 is 7877302013131.
It is a strong prime.
It is an emirp because it is prime and its reverse (7877302013131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313102037787 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313102032787) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656551018893 + 656551018894.
It is an arithmetic number, because the mean of its divisors is an integer number (656551018894).
Almost surely, 21313102037787 is an apocalyptic number.
1313102037787 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313102037787 is an equidigital number, since it uses as much as digits as its factorization.
1313102037787 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 148176, while the sum is 43.
The spelling of 1313102037787 in words is "one trillion, three hundred thirteen billion, one hundred two million, thirty-seven thousand, seven hundred eighty-seven".
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