13131041104433 has 4 divisors (see below), whose sum is σ = 15006904119360. Its totient is φ = 11255178089508.

The previous prime is 13131041104409. The next prime is 13131041104477. The reversal of 13131041104433 is 33440114013131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13131041104433 - 2⁸ = 13131041104177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13131041104396 and 13131041104405.

It is not an unprimeable number, because it can be changed into a prime (13131041154433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 937931507453 + ... + 937931507466.

It is an arithmetic number, because the mean of its divisors is an integer number (3751726029840).

Almost surely, 2^{13131041104433} is an apocalyptic number.

It is an amenable number.

13131041104433 is a deficient number, since it is larger than the sum of its proper divisors (1875863014927).

13131041104433 is an equidigital number, since it uses as much as digits as its factorization.

13131041104433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1875863014926.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13131041104433 its reverse (33440114013131), we get a palindrome (46571155117564).

The spelling of 13131041104433 in words is "thirteen trillion, one hundred thirty-one billion, forty-one million, one hundred four thousand, four hundred thirty-three".