131310433433 has 4 divisors (see below), whose sum is σ = 131313784080. Its totient is φ = 131307082788.

The previous prime is 131310433427. The next prime is 131310433469. The reversal of 131310433433 is 334334013131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131310433433 - 2²⁴ = 131293656217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131310433396 and 131310433405.

It is not an unprimeable number, because it can be changed into a prime (131310433633) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1615835 + ... + 1695152.

It is an arithmetic number, because the mean of its divisors is an integer number (32828446020).

Almost surely, 2^131310433433 is an apocalyptic number.

It is an amenable number.

131310433433 is a deficient number, since it is larger than the sum of its proper divisors (3350647).

131310433433 is an equidigital number, since it uses as much as digits as its factorization.

131310433433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3350646.

The product of its (nonzero) digits is 11664, while the sum is 29.

Adding to 131310433433 its reverse (334334013131), we get a palindrome (465644446564).

The spelling of 131310433433 in words is "one hundred thirty-one billion, three hundred ten million, four hundred thirty-three thousand, four hundred thirty-three".