13131044513131 has 2 divisors, whose sum is σ = 13131044513132. Its totient is φ = 13131044513130.

The previous prime is 13131044513101. The next prime is 13131044513141. The reversal of 13131044513131 is 13131544013131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13131044513131 - 2⁵ = 13131044513099 is a prime.

It is a super-2 number, since 2×13131044513131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13131044513093 and 13131044513102.

It is not a weakly prime, because it can be changed into another prime (13131044513101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565522256565 + 6565522256566.

It is an arithmetic number, because the mean of its divisors is an integer number (6565522256566).

Almost surely, 2^{13131044513131} is an apocalyptic number.

13131044513131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131044513131 is an equidigital number, since it uses as much as digits as its factorization.

13131044513131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 13131044513131 its reverse (13131544013131), we get a palindrome (26262588526262).

The spelling of 13131044513131 in words is "thirteen trillion, one hundred thirty-one billion, forty-four million, five hundred thirteen thousand, one hundred thirty-one".