13131100232320 has 256 divisors, whose sum is σ = 35964793566720. Its totient is φ = 4490969333760.

The previous prime is 13131100232267. The next prime is 13131100232351. The reversal of 13131100232320 is 2323200113131.

It is a super-2 number, since 2×13131100232320² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13131100232291 and 13131100232300.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4843635765 + ... + 4843638475.

It is an arithmetic number, because the mean of its divisors is an integer number (140487474870).

Almost surely, 2^{13131100232320} is an apocalyptic number.

13131100232320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13131100232320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17982396783360).

13131100232320 is an abundant number, since it is smaller than the sum of its proper divisors (22833693334400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131100232320 is a wasteful number, since it uses less digits than its factorization.

13131100232320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5011 (or 4999 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13131100232320 its reverse (2323200113131), we get a palindrome (15454300345451).

The spelling of 13131100232320 in words is "thirteen trillion, one hundred thirty-one billion, one hundred million, two hundred thirty-two thousand, three hundred twenty".