Base | Representation |
---|---|
bin | 1011111100010101001010… |
… | …1010111100001011011010 |
3 | 1201111022200002001210100002 |
4 | 2333011102222330023122 |
5 | 3210114444103341442 |
6 | 43532202303413002 |
7 | 2523455643332153 |
oct | 277052252741332 |
9 | 51438602053302 |
10 | 13131102012122 |
11 | 4202961838946 |
12 | 1580a8b5b4162 |
13 | 743346c66713 |
14 | 3357979d492a |
15 | 17b88412c732 |
hex | bf152abc2da |
13131102012122 has 8 divisors (see below), whose sum is σ = 19814597048736. Its totient is φ = 6526236329212.
The previous prime is 13131102012113. The next prime is 13131102012143. The reversal of 13131102012122 is 22121020113131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×131311020121223 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13131102012094 and 13131102012103.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19657338008 + ... + 19657338675.
It is an arithmetic number, because the mean of its divisors is an integer number (2476824631092).
Almost surely, 213131102012122 is an apocalyptic number.
13131102012122 is a deficient number, since it is larger than the sum of its proper divisors (6683495036614).
13131102012122 is a wasteful number, since it uses less digits than its factorization.
13131102012122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39314676852.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 13131102012122 its reverse (22121020113131), we get a palindrome (35252122125253).
The spelling of 13131102012122 in words is "thirteen trillion, one hundred thirty-one billion, one hundred two million, twelve thousand, one hundred twenty-two".
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