Base | Representation |
---|---|
bin | 111101001001010111… |
… | …1110100111111001011 |
3 | 110112221021212110222121 |
4 | 1322102233310333023 |
5 | 4122411110431334 |
6 | 140153511032111 |
7 | 12326003224615 |
oct | 1722257647713 |
9 | 415837773877 |
10 | 131311030219 |
11 | 50763720586 |
12 | 2154796b637 |
13 | c4c86a2265 |
14 | 64d965bdb5 |
15 | 3637ed1db4 |
hex | 1e92bf4fcb |
131311030219 has 2 divisors, whose sum is σ = 131311030220. Its totient is φ = 131311030218.
The previous prime is 131311030189. The next prime is 131311030223. The reversal of 131311030219 is 912030113131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131311030219 - 217 = 131310899147 is a prime.
It is a super-2 number, since 2×1313110302192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131311030193 and 131311030202.
It is not a weakly prime, because it can be changed into another prime (131311030519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655515109 + 65655515110.
It is an arithmetic number, because the mean of its divisors is an integer number (65655515110).
Almost surely, 2131311030219 is an apocalyptic number.
131311030219 is a deficient number, since it is larger than the sum of its proper divisors (1).
131311030219 is an equidigital number, since it uses as much as digits as its factorization.
131311030219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 25.
The spelling of 131311030219 in words is "one hundred thirty-one billion, three hundred eleven million, thirty thousand, two hundred nineteen".
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