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1313110322122 = 2656555161061
BaseRepresentation
bin10011000110111011011…
…110010110101111001010
311122112100220201211012011
4103012323132112233022
5133003222220301442
62443122355210134
7163604045402014
oct23067336265712
94575326654164
101313110322122
114669835a9255
121925a5ba694a
1396a972b4cb1
14477aa8311b4
1524254dba117
hex131bb796bca

1313110322122 has 4 divisors (see below), whose sum is σ = 1969665483186. Its totient is φ = 656555161060.

The previous prime is 1313110322099. The next prime is 1313110322123. The reversal of 1313110322122 is 2212230113131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 927867901081 + 385242421041 = 963259^2 + 620679^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1313110322093 and 1313110322102.

It is not an unprimeable number, because it can be changed into a prime (1313110322123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328277580529 + ... + 328277580532.

Almost surely, 21313110322122 is an apocalyptic number.

1313110322122 is a deficient number, since it is larger than the sum of its proper divisors (656555161064).

1313110322122 is an equidigital number, since it uses as much as digits as its factorization.

1313110322122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 656555161063.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1313110322122 its reverse (2212230113131), we get a palindrome (3525340435253).

The spelling of 1313110322122 in words is "one trillion, three hundred thirteen billion, one hundred ten million, three hundred twenty-two thousand, one hundred twenty-two".

Divisors: 1 2 656555161061 1313110322122