1313111312081 has 2 divisors, whose sum is σ = 1313111312082. Its totient is φ = 1313111312080.

The previous prime is 1313111311973. The next prime is 1313111312263. The reversal of 1313111312081 is 1802131113131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1223698351681 + 89412960400 = 1106209^2 + 299020^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313111312081 - 2¹⁴ = 1313111295697 is a prime.

It is a super-2 number, since 2×1313111312081² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1313111312081.

It is not a weakly prime, because it can be changed into another prime (1313111315081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656555656040 + 656555656041.

It is an arithmetic number, because the mean of its divisors is an integer number (656555656041).

Almost surely, 2^{1313111312081} is an apocalyptic number.

It is an amenable number.

1313111312081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313111312081 is an equidigital number, since it uses as much as digits as its factorization.

1313111312081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 26.

The spelling of 1313111312081 in words is "one trillion, three hundred thirteen billion, one hundred eleven million, three hundred twelve thousand, eighty-one".