Base | Representation |
---|---|
bin | 10011000110111011100… |
… | …101100111000110011001 |
3 | 11122112101001022110021202 |
4 | 103012323211213012121 |
5 | 133003223212133103 |
6 | 2443122504043545 |
7 | 163604100513212 |
oct | 23067345470631 |
9 | 4575331273252 |
10 | 1313112224153 |
11 | 466984688284 |
12 | 1925a67635b5 |
13 | 96a977cc962 |
14 | 477aaba8409 |
15 | 24255143988 |
hex | 131bb967199 |
1313112224153 has 4 divisors (see below), whose sum is σ = 1313866454628. Its totient is φ = 1312357993680.
The previous prime is 1313112224147. The next prime is 1313112224161. The reversal of 1313112224153 is 3514222113131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7584319744 + 1305527904409 = 87088^2 + 1142597^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313112224153 - 214 = 1313112207769 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1313112224173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 377112626 + ... + 377116107.
It is an arithmetic number, because the mean of its divisors is an integer number (328466613657).
Almost surely, 21313112224153 is an apocalyptic number.
It is an amenable number.
1313112224153 is a deficient number, since it is larger than the sum of its proper divisors (754230475).
1313112224153 is an equidigital number, since it uses as much as digits as its factorization.
1313112224153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 754230474.
The product of its digits is 4320, while the sum is 29.
Adding to 1313112224153 its reverse (3514222113131), we get a palindrome (4827334337284).
The spelling of 1313112224153 in words is "one trillion, three hundred thirteen billion, one hundred twelve million, two hundred twenty-four thousand, one hundred fifty-three".
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