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1313112224153 = 1741754228733
BaseRepresentation
bin10011000110111011100…
…101100111000110011001
311122112101001022110021202
4103012323211213012121
5133003223212133103
62443122504043545
7163604100513212
oct23067345470631
94575331273252
101313112224153
11466984688284
121925a67635b5
1396a977cc962
14477aaba8409
1524255143988
hex131bb967199

1313112224153 has 4 divisors (see below), whose sum is σ = 1313866454628. Its totient is φ = 1312357993680.

The previous prime is 1313112224147. The next prime is 1313112224161. The reversal of 1313112224153 is 3514222113131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7584319744 + 1305527904409 = 87088^2 + 1142597^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313112224153 - 214 = 1313112207769 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313112224173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 377112626 + ... + 377116107.

It is an arithmetic number, because the mean of its divisors is an integer number (328466613657).

Almost surely, 21313112224153 is an apocalyptic number.

It is an amenable number.

1313112224153 is a deficient number, since it is larger than the sum of its proper divisors (754230475).

1313112224153 is an equidigital number, since it uses as much as digits as its factorization.

1313112224153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 754230474.

The product of its digits is 4320, while the sum is 29.

Adding to 1313112224153 its reverse (3514222113131), we get a palindrome (4827334337284).

The spelling of 1313112224153 in words is "one trillion, three hundred thirteen billion, one hundred twelve million, two hundred twenty-four thousand, one hundred fifty-three".

Divisors: 1 1741 754228733 1313112224153