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131312041123 is a prime number
BaseRepresentation
bin111101001001011001…
…1101011110010100011
3110112221100202211200111
41322102303223302203
54122411340303443
6140153544432151
712326014635064
oct1722263536243
9415840684614
10131312041123
115076425103a
1221548178657
13c4c8967423
1464d984256b
15363813169d
hex1e92cebca3

131312041123 has 2 divisors, whose sum is σ = 131312041124. Its totient is φ = 131312041122.

The previous prime is 131312041109. The next prime is 131312041129. The reversal of 131312041123 is 321140213131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131312041123 is a prime.

It is a super-2 number, since 2×1313120411232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131312041094 and 131312041103.

It is not a weakly prime, because it can be changed into another prime (131312041129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656020561 + 65656020562.

It is an arithmetic number, because the mean of its divisors is an integer number (65656020562).

Almost surely, 2131312041123 is an apocalyptic number.

131312041123 is a deficient number, since it is larger than the sum of its proper divisors (1).

131312041123 is an equidigital number, since it uses as much as digits as its factorization.

131312041123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 131312041123 its reverse (321140213131), we get a palindrome (452452254254).

The spelling of 131312041123 in words is "one hundred thirty-one billion, three hundred twelve million, forty-one thousand, one hundred twenty-three".