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131312110302601 is a prime number
BaseRepresentation
bin11101110110110101111011…
…101100000111010110001001
3122012221022111202000212001221
4131312311323230013112021
5114202404200214140401
61143135541203242041
736441662335231624
oct3566657354072611
9565838452025057
10131312110302601
1138927175a69a68
1212889200079321
1358368a9624147
14245d77bc78dbb
15102aae177b7a1
hex776d7bb07589

131312110302601 has 2 divisors, whose sum is σ = 131312110302602. Its totient is φ = 131312110302600.

The previous prime is 131312110302481. The next prime is 131312110302617. The reversal of 131312110302601 is 106203011213131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83054788633600 + 48257321669001 = 9113440^2 + 6946749^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131312110302601 is a prime.

It is not a weakly prime, because it can be changed into another prime (131312110302691) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656055151300 + 65656055151301.

It is an arithmetic number, because the mean of its divisors is an integer number (65656055151301).

Almost surely, 2131312110302601 is an apocalyptic number.

It is an amenable number.

131312110302601 is a deficient number, since it is larger than the sum of its proper divisors (1).

131312110302601 is an equidigital number, since it uses as much as digits as its factorization.

131312110302601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 131312110302601 its reverse (106203011213131), we get a palindrome (237515121515732).

The spelling of 131312110302601 in words is "one hundred thirty-one trillion, three hundred twelve billion, one hundred ten million, three hundred two thousand, six hundred one".