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1313121213000 = 2335537277433
BaseRepresentation
bin10011000110111100000…
…111111001101001001000
311122112101200020010200000
4103012330013321221020
5133003233012304000
62443123424443000
7163604240101602
oct23067407715110
94575350203600
101313121213000
11466989767783
121925a9779460
1396a996291bc
14477ac068172
1524255d1c000
hex131bc1f9a48

1313121213000 has 384 divisors, whose sum is σ = 4609684235520. Its totient is φ = 349636953600.

The previous prime is 1313121212993. The next prime is 1313121213007. The reversal of 1313121213000 is 3121213131.

1313121213000 is a `hidden beast` number, since 1 + 31 + 312 + 1 + 21 + 300 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (1313121212993) and next prime (1313121213007).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (1313121213007) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 176657284 + ... + 176664716.

It is an arithmetic number, because the mean of its divisors is an integer number (12004386030).

Almost surely, 21313121213000 is an apocalyptic number.

1313121213000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1313121213000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2304842117760).

1313121213000 is an abundant number, since it is smaller than the sum of its proper divisors (3296563022520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313121213000 is an equidigital number, since it uses as much as digits as its factorization.

1313121213000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8196 (or 8170 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1313121213000 its reverse (3121213131), we get a palindrome (1316242426131).

The spelling of 1313121213000 in words is "one trillion, three hundred thirteen billion, one hundred twenty-one million, two hundred thirteen thousand".