Base | Representation |
---|---|
bin | 10011000110111100000… |
… | …111111110000110001001 |
3 | 11122112101200021001200121 |
4 | 103012330013332012021 |
5 | 133003233013344431 |
6 | 2443123425103241 |
7 | 163604240206021 |
oct | 23067407760611 |
9 | 4575350231617 |
10 | 1313121231241 |
11 | 46698977a456 |
12 | 1925a9787b21 |
13 | 96a996345b1 |
14 | 477ac070a81 |
15 | 24255d22611 |
hex | 131bc1fe189 |
1313121231241 has 2 divisors, whose sum is σ = 1313121231242. Its totient is φ = 1313121231240.
The previous prime is 1313121231179. The next prime is 1313121231263. The reversal of 1313121231241 is 1421321213131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1291850467216 + 21270764025 = 1136596^2 + 145845^2 .
It is an emirp because it is prime and its reverse (1421321213131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313121231241 - 237 = 1175682277769 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313121231641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656560615620 + 656560615621.
It is an arithmetic number, because the mean of its divisors is an integer number (656560615621).
Almost surely, 21313121231241 is an apocalyptic number.
It is an amenable number.
1313121231241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313121231241 is an equidigital number, since it uses as much as digits as its factorization.
1313121231241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 864, while the sum is 25.
Adding to 1313121231241 its reverse (1421321213131), we get a palindrome (2734442444372).
The spelling of 1313121231241 in words is "one trillion, three hundred thirteen billion, one hundred twenty-one million, two hundred thirty-one thousand, two hundred forty-one".
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