Base | Representation |
---|---|
bin | 11101110110110110110111… |
… | …011001011001101100110011 |
3 | 122012221102002112221212201211 |
4 | 131312312313121121230303 |
5 | 114202413223134430003 |
6 | 1143140224425540551 |
7 | 36442026220615651 |
oct | 3566666731315463 |
9 | 565842075855654 |
10 | 131313112030003 |
11 | 3892763a462652 |
12 | 1288943b644757 |
13 | 5836a09017657 |
14 | 245d834d15dd1 |
15 | 102ab4e69e96d |
hex | 776db7659b33 |
131313112030003 has 4 divisors (see below), whose sum is σ = 131797662259168. Its totient is φ = 130828561800840.
The previous prime is 131313112029997. The next prime is 131313112030013. The reversal of 131313112030003 is 300030211313131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131313112030003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131313112030013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242275114176 + ... + 242275114717.
It is an arithmetic number, because the mean of its divisors is an integer number (32949415564792).
Almost surely, 2131313112030003 is an apocalyptic number.
131313112030003 is a deficient number, since it is larger than the sum of its proper divisors (484550229165).
131313112030003 is an equidigital number, since it uses as much as digits as its factorization.
131313112030003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 484550229164.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 131313112030003 its reverse (300030211313131), we get a palindrome (431343323343134).
The spelling of 131313112030003 in words is "one hundred thirty-one trillion, three hundred thirteen billion, one hundred twelve million, thirty thousand, three".
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