Base | Representation |
---|---|
bin | 10011000110111100110… |
… | …100111011011101101011 |
3 | 11122112102111102211121221 |
4 | 103012330310323131223 |
5 | 133003244023020224 |
6 | 2443124525442511 |
7 | 163604442323452 |
oct | 23067464733553 |
9 | 4575374384557 |
10 | 1313133016939 |
11 | 46699539a1a7 |
12 | 1925b1710437 |
13 | 96a9bbccb93 |
14 | 477ad85bb99 |
15 | 24256d9e6e4 |
hex | 131bcd3b76b |
1313133016939 has 2 divisors, whose sum is σ = 1313133016940. Its totient is φ = 1313133016938.
The previous prime is 1313133016933. The next prime is 1313133016963. The reversal of 1313133016939 is 9396103313131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313133016939 - 25 = 1313133016907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313133016895 and 1313133016904.
It is not a weakly prime, because it can be changed into another prime (1313133016933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656566508469 + 656566508470.
It is an arithmetic number, because the mean of its divisors is an integer number (656566508470).
Almost surely, 21313133016939 is an apocalyptic number.
1313133016939 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313133016939 is an equidigital number, since it uses as much as digits as its factorization.
1313133016939 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 118098, while the sum is 43.
The spelling of 1313133016939 in words is "one trillion, three hundred thirteen billion, one hundred thirty-three million, sixteen thousand, nine hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •