Base | Representation |
---|---|
bin | 10011000110111100110… |
… | …101000000001100100011 |
3 | 11122112102111110211012212 |
4 | 103012330311000030203 |
5 | 133003244024130243 |
6 | 2443124530112335 |
7 | 163604442434123 |
oct | 23067465001443 |
9 | 4575374424185 |
10 | 1313133036323 |
11 | 466995402819 |
12 | 1925b171b6ab |
13 | 96a9bc08954 |
14 | 477ad864c83 |
15 | 24256da5318 |
hex | 131bcd40323 |
1313133036323 has 2 divisors, whose sum is σ = 1313133036324. Its totient is φ = 1313133036322.
The previous prime is 1313133036253. The next prime is 1313133036359. The reversal of 1313133036323 is 3236303313131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313133036323 - 218 = 1313132774179 is a prime.
It is a super-2 number, since 2×13131330363232 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1313133036323.
It is not a weakly prime, because it can be changed into another prime (1313133036373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656566518161 + 656566518162.
It is an arithmetic number, because the mean of its divisors is an integer number (656566518162).
Almost surely, 21313133036323 is an apocalyptic number.
1313133036323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313133036323 is an equidigital number, since it uses as much as digits as its factorization.
1313133036323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 32.
Adding to 1313133036323 its reverse (3236303313131), we get a palindrome (4549436349454).
The spelling of 1313133036323 in words is "one trillion, three hundred thirteen billion, one hundred thirty-three million, thirty-six thousand, three hundred twenty-three".
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