Base | Representation |
---|---|
bin | 10011000110111101011… |
… | …011000011001101100011 |
3 | 11122112110012020112201202 |
4 | 103012331123003031203 |
5 | 133003304102311042 |
6 | 2443125523551415 |
7 | 163604623264253 |
oct | 23067533031543 |
9 | 4575405215652 |
10 | 1313143010147 |
11 | 46699aaa5251 |
12 | 1925b4b2b56b |
13 | 96aa0cbb617 |
14 | 477b0cdd963 |
15 | 24257bc5632 |
hex | 131bd6c3363 |
1313143010147 has 2 divisors, whose sum is σ = 1313143010148. Its totient is φ = 1313143010146.
The previous prime is 1313143010129. The next prime is 1313143010203. The reversal of 1313143010147 is 7410103413131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313143010147 - 212 = 1313143006051 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313143010117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656571505073 + 656571505074.
It is an arithmetic number, because the mean of its divisors is an integer number (656571505074).
Almost surely, 21313143010147 is an apocalyptic number.
1313143010147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313143010147 is an equidigital number, since it uses as much as digits as its factorization.
1313143010147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 1313143010147 its reverse (7410103413131), we get a palindrome (8723246423278).
The spelling of 1313143010147 in words is "one trillion, three hundred thirteen billion, one hundred forty-three million, ten thousand, one hundred forty-seven".
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