Search a number
-
+
131314451401 = 718759207343
BaseRepresentation
bin111101001001011110…
…0111000001111001001
3110112221112022021222001
41322102330320033021
54122412444421101
6140154112231001
712326044264120
oct1722274701711
9415845267861
10131314451401
1150765647a01
1221548b3b461
13c4c92cc523
1464d9cacab7
15363845a901
hex1e92f383c9

131314451401 has 4 divisors (see below), whose sum is σ = 150073658752. Its totient is φ = 112555244052.

The previous prime is 131314451369. The next prime is 131314451413. The reversal of 131314451401 is 104154413131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131314451401 - 25 = 131314451369 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131314451401.

It is not an unprimeable number, because it can be changed into a prime (131314451441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9379603665 + ... + 9379603678.

It is an arithmetic number, because the mean of its divisors is an integer number (37518414688).

Almost surely, 2131314451401 is an apocalyptic number.

It is an amenable number.

131314451401 is a deficient number, since it is larger than the sum of its proper divisors (18759207351).

131314451401 is an equidigital number, since it uses as much as digits as its factorization.

131314451401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18759207350.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 131314451401 its reverse (104154413131), we get a palindrome (235468864532).

The spelling of 131314451401 in words is "one hundred thirty-one billion, three hundred fourteen million, four hundred fifty-one thousand, four hundred one".

Divisors: 1 7 18759207343 131314451401