Base | Representation |
---|---|
bin | 11101110110111000010110… |
… | …101010110010111010011010 |
3 | 122012221120012221121202210111 |
4 | 131312320112222302322122 |
5 | 114202430011332101432 |
6 | 1143141051205034534 |
7 | 36442113640013251 |
oct | 3566702652627232 |
9 | 565846187552714 |
10 | 131314710425242 |
11 | 3892828a738653 |
12 | 128898069b5a4a |
13 | 5836c0220ab56 |
14 | 245d94730d798 |
15 | 102abe4b83347 |
hex | 776e16ab2e9a |
131314710425242 has 8 divisors (see below), whose sum is σ = 196973827467732. Its totient is φ = 65656767936000.
The previous prime is 131314710425219. The next prime is 131314710425267. The reversal of 131314710425242 is 242524017413131.
It can be written as a sum of positive squares in 2 ways, for example, as 130893300421321 + 421410003921 = 11440861^2 + 649161^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 131314710425195 and 131314710425204.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 293358759 + ... + 293806042.
Almost surely, 2131314710425242 is an apocalyptic number.
131314710425242 is a deficient number, since it is larger than the sum of its proper divisors (65659117042490).
131314710425242 is a wasteful number, since it uses less digits than its factorization.
131314710425242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 587276624.
The product of its (nonzero) digits is 161280, while the sum is 40.
Adding to 131314710425242 its reverse (242524017413131), we get a palindrome (373838727838373).
The spelling of 131314710425242 in words is "one hundred thirty-one trillion, three hundred fourteen billion, seven hundred ten million, four hundred twenty-five thousand, two hundred forty-two".
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