131314710426011 has 4 divisors (see below), whose sum is σ = 150073954772592. Its totient is φ = 112555466079432.

The previous prime is 131314710425993. The next prime is 131314710426013. The reversal of 131314710426011 is 110624017413131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131314710426011 - 2¹⁴ = 131314710409627 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131314710426013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9379622173280 + ... + 9379622173293.

It is an arithmetic number, because the mean of its divisors is an integer number (37518488693148).

Almost surely, 2^{131314710426011} is an apocalyptic number.

131314710426011 is a deficient number, since it is larger than the sum of its proper divisors (18759244346581).

131314710426011 is an equidigital number, since it uses as much as digits as its factorization.

131314710426011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18759244346580.

The product of its (nonzero) digits is 12096, while the sum is 35.

Adding to 131314710426011 its reverse (110624017413131), we get a palindrome (241938727839142).

The spelling of 131314710426011 in words is "one hundred thirty-one trillion, three hundred fourteen billion, seven hundred ten million, four hundred twenty-six thousand, eleven".