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13131511040353 = 148369259127849
BaseRepresentation
bin1011111100010110101100…
…0011010000100101100001
31201111100201120201120120211
42333011223003100211201
53210121313311242403
643532311034334121
72523502041115246
oct277055303204541
951440646646524
1013131511040353
11420305170a902
121580b8458a341
137433b0919464
143357d60695cd
1517b8a9ec606d
hexbf16b0d0961

13131511040353 has 8 divisors (see below), whose sum is σ = 13140658244000. Its totient is φ = 13122364233888.

The previous prime is 13131511040309. The next prime is 13131511040371. The reversal of 13131511040353 is 35304011513131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13131511040353 - 213 = 13131511032161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13131511041353) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102647173 + ... + 102775021.

It is an arithmetic number, because the mean of its divisors is an integer number (1642582280500).

Almost surely, 213131511040353 is an apocalyptic number.

It is an amenable number.

13131511040353 is a deficient number, since it is larger than the sum of its proper divisors (9147203647).

13131511040353 is a wasteful number, since it uses less digits than its factorization.

13131511040353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 198591.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 13131511040353 its reverse (35304011513131), we get a palindrome (48435522553484).

The spelling of 13131511040353 in words is "thirteen trillion, one hundred thirty-one billion, five hundred eleven million, forty thousand, three hundred fifty-three".

Divisors: 1 1483 69259 127849 102711097 189600067 8854693891 13131511040353