Base | Representation |
---|---|
bin | 10011000111000000110… |
… | …101101110001000011011 |
3 | 11122112121012002212100221 |
4 | 103013000311232020123 |
5 | 133003413241131324 |
6 | 2443135332340511 |
7 | 163606220442256 |
oct | 23070065561033 |
9 | 4575535085327 |
10 | 1313200333339 |
11 | 466a1a397a94 |
12 | 192610174737 |
13 | 96aacb3c07b |
14 | 477b878209d |
15 | 2425cc4a0e4 |
hex | 131c0d6e21b |
1313200333339 has 2 divisors, whose sum is σ = 1313200333340. Its totient is φ = 1313200333338.
The previous prime is 1313200333309. The next prime is 1313200333363. The reversal of 1313200333339 is 9333330023131.
It is a strong prime.
It is an emirp because it is prime and its reverse (9333330023131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313200333339 - 211 = 1313200331291 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313200333309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656600166669 + 656600166670.
It is an arithmetic number, because the mean of its divisors is an integer number (656600166670).
Almost surely, 21313200333339 is an apocalyptic number.
1313200333339 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313200333339 is an equidigital number, since it uses as much as digits as its factorization.
1313200333339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 39366, while the sum is 34.
The spelling of 1313200333339 in words is "one trillion, three hundred thirteen billion, two hundred million, three hundred thirty-three thousand, three hundred thirty-nine".
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