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13132012023001 is a prime number
BaseRepresentation
bin1011111100011000100011…
…1010010110110011011001
31201111102000111102010120201
42333012020322112303121
53210123330034214001
643532432452222201
72523520333314124
oct277061072266331
951442014363521
1013132012023001
114203289488553
1215810a430a961
137434606568b1
143358427d93bb
1517b8d8e85501
hexbf188e96cd9

13132012023001 has 2 divisors, whose sum is σ = 13132012023002. Its totient is φ = 13132012023000.

The previous prime is 13132012022981. The next prime is 13132012023023. The reversal of 13132012023001 is 10032021023131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9574352120025 + 3557659902976 = 3094245^2 + 1886176^2 .

It is an emirp because it is prime and its reverse (10032021023131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13132012023001 - 27 = 13132012022873 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13132012023001.

It is not a weakly prime, because it can be changed into another prime (13132012023061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566006011500 + 6566006011501.

It is an arithmetic number, because the mean of its divisors is an integer number (6566006011501).

Almost surely, 213132012023001 is an apocalyptic number.

It is an amenable number.

13132012023001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13132012023001 is an equidigital number, since it uses as much as digits as its factorization.

13132012023001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13132012023001 its reverse (10032021023131), we get a palindrome (23164033046132).

The spelling of 13132012023001 in words is "thirteen trillion, one hundred thirty-two billion, twelve million, twenty-three thousand, one".