Base | Representation |
---|---|
bin | 1011111100011000100011… |
… | …1110110110011101101001 |
3 | 1201111102000120121222211211 |
4 | 2333012020332312131221 |
5 | 3210123330334420012 |
6 | 43532432533353121 |
7 | 2523520346322226 |
oct | 277061076663551 |
9 | 51442016558754 |
10 | 13132013201257 |
11 | 420328a112815 |
12 | 15810a47987a1 |
13 | 743460979ca2 |
14 | 335842a2494d |
15 | 17b8d91196a7 |
hex | bf188fb6769 |
13132013201257 has 4 divisors (see below), whose sum is σ = 13132094672016. Its totient is φ = 13131931730500.
The previous prime is 13132013201231. The next prime is 13132013201299. The reversal of 13132013201257 is 75210231023131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13132013201257 - 219 = 13132012676969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13132013201227) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40493119 + ... + 40816132.
It is an arithmetic number, because the mean of its divisors is an integer number (3283023668004).
Almost surely, 213132013201257 is an apocalyptic number.
It is an amenable number.
13132013201257 is a deficient number, since it is larger than the sum of its proper divisors (81470759).
13132013201257 is an equidigital number, since it uses as much as digits as its factorization.
13132013201257 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81470758.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 13132013201257 its reverse (75210231023131), we get a palindrome (88342244224388).
The spelling of 13132013201257 in words is "thirteen trillion, one hundred thirty-two billion, thirteen million, two hundred one thousand, two hundred fifty-seven".
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