Base | Representation |
---|---|
bin | 1011111100011000100100… |
… | …0000111100101111010010 |
3 | 1201111102000121122221021221 |
4 | 2333012021000330233102 |
5 | 3210123331010020000 |
6 | 43532432553235254 |
7 | 2523520354102552 |
oct | 277061100745722 |
9 | 51442017587257 |
10 | 13132013751250 |
11 | 420328a458a59 |
12 | 15810a4a02b2a |
13 | 743460b10424 |
14 | 335842b29162 |
15 | 17b8d91c761a |
hex | bf18903cbd2 |
13132013751250 has 40 divisors (see below), whose sum is σ = 24615127825200. Its totient is φ = 5252702802000.
The previous prime is 13132013751221. The next prime is 13132013751271. The reversal of 13132013751250 is 5215731023131.
13132013751250 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 120269181 + ... + 120378319.
It is an arithmetic number, because the mean of its divisors is an integer number (615378195630).
Almost surely, 213132013751250 is an apocalyptic number.
13132013751250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13132013751250 is a deficient number, since it is larger than the sum of its proper divisors (11483114073950).
13132013751250 is an equidigital number, since it uses as much as digits as its factorization.
13132013751250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 205420 (or 205405 counting only the distinct ones).
The product of its (nonzero) digits is 18900, while the sum is 34.
Adding to 13132013751250 its reverse (5215731023131), we get a palindrome (18347744774381).
The spelling of 13132013751250 in words is "thirteen trillion, one hundred thirty-two billion, thirteen million, seven hundred fifty-one thousand, two hundred fifty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •