Base | Representation |
---|---|
bin | 10011000111000001000… |
… | …001000101101011001001 |
3 | 11122112121101201021011211 |
4 | 103013001001011223021 |
5 | 133003420022011403 |
6 | 2443135520253121 |
7 | 163606254663331 |
oct | 23070101055311 |
9 | 4575541637154 |
10 | 1313203313353 |
11 | 466a21042a08 |
12 | 1926111711a1 |
13 | 96ab06435a9 |
14 | 477b8d1a0c1 |
15 | 2425d13806d |
hex | 131c1045ac9 |
1313203313353 has 2 divisors, whose sum is σ = 1313203313354. Its totient is φ = 1313203313352.
The previous prime is 1313203313341. The next prime is 1313203313423. The reversal of 1313203313353 is 3533133023131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1255090014864 + 58113298489 = 1120308^2 + 241067^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313203313353 - 229 = 1312666442441 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313203353353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656601656676 + 656601656677.
It is an arithmetic number, because the mean of its divisors is an integer number (656601656677).
Almost surely, 21313203313353 is an apocalyptic number.
It is an amenable number.
1313203313353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313203313353 is an equidigital number, since it uses as much as digits as its factorization.
1313203313353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21870, while the sum is 31.
Adding to 1313203313353 its reverse (3533133023131), we get a palindrome (4846336336484).
The spelling of 1313203313353 in words is "one trillion, three hundred thirteen billion, two hundred three million, three hundred thirteen thousand, three hundred fifty-three".
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