Base | Representation |
---|---|
bin | 11000011101011101… |
… | …11111110111011011 |
3 | 1020220012100221220001 |
4 | 30032232333313123 |
5 | 203343304300011 |
6 | 10011030313431 |
7 | 643266014650 |
oct | 141656776733 |
9 | 36805327801 |
10 | 13132103131 |
11 | 56298034a4 |
12 | 2665ab8877 |
13 | 1313875834 |
14 | 8c8115c27 |
15 | 51cd487c1 |
hex | 30ebbfddb |
13132103131 has 8 divisors (see below), whose sum is σ = 15011912160. Its totient is φ = 11253242688.
The previous prime is 13132103093. The next prime is 13132103177. The reversal of 13132103131 is 13130123131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13132103131 - 221 = 13130005979 is a prime.
It is a super-2 number, since 2×131321031312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13132103099 and 13132103108.
It is not an unprimeable number, because it can be changed into a prime (13132103191) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 207226 + ... + 263071.
It is an arithmetic number, because the mean of its divisors is an integer number (1876489020).
Almost surely, 213132103131 is an apocalyptic number.
13132103131 is a deficient number, since it is larger than the sum of its proper divisors (1879809029).
13132103131 is an equidigital number, since it uses as much as digits as its factorization.
13132103131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 474293.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13132103131 its reverse (13130123131), we get a palindrome (26262226262).
The spelling of 13132103131 in words is "thirteen billion, one hundred thirty-two million, one hundred three thousand, one hundred thirty-one".
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