Base | Representation |
---|---|
bin | 10011000111000010001… |
… | …001001110010101111011 |
3 | 11122112122201021222122112 |
4 | 103013002021032111323 |
5 | 133003434342120402 |
6 | 2443141433442535 |
7 | 163606604502215 |
oct | 23070211162573 |
9 | 4575581258575 |
10 | 1313222223227 |
11 | 466a30789202 |
12 | 19261757044b |
13 | 96ab4534775 |
14 | 477bb63d5b5 |
15 | 2425eb20e52 |
hex | 131c224e57b |
1313222223227 has 2 divisors, whose sum is σ = 1313222223228. Its totient is φ = 1313222223226.
The previous prime is 1313222223121. The next prime is 1313222223233. The reversal of 1313222223227 is 7223222223131.
It is a strong prime.
It is an emirp because it is prime and its reverse (7223222223131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313222223227 - 210 = 1313222222203 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313222223193 and 1313222223202.
It is not a weakly prime, because it can be changed into another prime (1333222223227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656611111613 + 656611111614.
It is an arithmetic number, because the mean of its divisors is an integer number (656611111614).
Almost surely, 21313222223227 is an apocalyptic number.
1313222223227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313222223227 is an equidigital number, since it uses as much as digits as its factorization.
1313222223227 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24192, while the sum is 32.
Adding to 1313222223227 its reverse (7223222223131), we get a palindrome (8536444446358).
The spelling of 1313222223227 in words is "one trillion, three hundred thirteen billion, two hundred twenty-two million, two hundred twenty-three thousand, two hundred twenty-seven".
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