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13132301301011 = 28146734168331
BaseRepresentation
bin1011111100011001101000…
…1001110111010100010011
31201111102202122201222102002
42333012122021313110103
53210124423113113021
643532521304344215
72523530445166214
oct277063211672423
951442678658362
1013132301301011
1142034177a9392
12158116517506b
137434a856c309
1433586cdbb40b
1517b90457750b
hexbf19a277513

13132301301011 has 4 divisors (see below), whose sum is σ = 13179035469624. Its totient is φ = 13085567132400.

The previous prime is 13132301300969. The next prime is 13132301301017. The reversal of 13132301301011 is 11010310323131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13132301301011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13132301301017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23367083885 + ... + 23367084446.

It is an arithmetic number, because the mean of its divisors is an integer number (3294758867406).

Almost surely, 213132301301011 is an apocalyptic number.

13132301301011 is a deficient number, since it is larger than the sum of its proper divisors (46734168613).

13132301301011 is an equidigital number, since it uses as much as digits as its factorization.

13132301301011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46734168612.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 13132301301011 its reverse (11010310323131), we get a palindrome (24142611624142).

The spelling of 13132301301011 in words is "thirteen trillion, one hundred thirty-two billion, three hundred one million, three hundred one thousand, eleven".

Divisors: 1 281 46734168331 13132301301011