Base | Representation |
---|---|
bin | 11101110111000000001011… |
… | …100000100010010110010011 |
3 | 122012222100220112202221122211 |
4 | 131313000023200202112103 |
5 | 114203044213424334141 |
6 | 1143145001052012551 |
7 | 36442532110524106 |
oct | 3567001340422623 |
9 | 565870815687584 |
10 | 131323113121171 |
11 | 38930901852454 |
12 | 1288b370a61157 |
13 | 5837940cc768a |
14 | 246010328073d |
15 | 102b0376c5d81 |
hex | 77700b822593 |
131323113121171 has 2 divisors, whose sum is σ = 131323113121172. Its totient is φ = 131323113121170.
The previous prime is 131323113121157. The next prime is 131323113121259. The reversal of 131323113121171 is 171121311323131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131323113121171 - 27 = 131323113121043 is a prime.
It is a super-2 number, since 2×1313231131211712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131323113121141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65661556560585 + 65661556560586.
It is an arithmetic number, because the mean of its divisors is an integer number (65661556560586).
Almost surely, 2131323113121171 is an apocalyptic number.
131323113121171 is a deficient number, since it is larger than the sum of its proper divisors (1).
131323113121171 is an equidigital number, since it uses as much as digits as its factorization.
131323113121171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2268, while the sum is 31.
The spelling of 131323113121171 in words is "one hundred thirty-one trillion, three hundred twenty-three billion, one hundred thirteen million, one hundred twenty-one thousand, one hundred seventy-one".
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