131323311310033 has 4 divisors (see below), whose sum is σ = 131323522846720. Its totient is φ = 131323099773348.

The previous prime is 131323311309973. The next prime is 131323311310091. The reversal of 131323311310033 is 330013113323131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131323311310033 - 2²⁹ = 131322774439121 is a prime.

It is a super-3 number, since 3×131323311310033³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131323311309983 and 131323311310010.

It is not an unprimeable number, because it can be changed into a prime (131323311314033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104834385 + ... + 106079662.

It is an arithmetic number, because the mean of its divisors is an integer number (32830880711680).

Almost surely, 2^{131323311310033} is an apocalyptic number.

It is an amenable number.

131323311310033 is a deficient number, since it is larger than the sum of its proper divisors (211536687).

131323311310033 is an equidigital number, since it uses as much as digits as its factorization.

131323311310033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211536686.

The product of its (nonzero) digits is 4374, while the sum is 28.

Adding to 131323311310033 its reverse (330013113323131), we get a palindrome (461336424633164).

The spelling of 131323311310033 in words is "one hundred thirty-one trillion, three hundred twenty-three billion, three hundred eleven million, three hundred ten thousand, thirty-three".