Base | Representation |
---|---|
bin | 11000011101011111… |
… | …10111110100100001 |
3 | 1020220012210121021120 |
4 | 30032233313310201 |
5 | 203343334113241 |
6 | 10011035242453 |
7 | 643300661103 |
oct | 141657676441 |
9 | 36805717246 |
10 | 13132332321 |
11 | 562994a709 |
12 | 2665ba9429 |
13 | 1313925c54 |
14 | 8c8175573 |
15 | 51cd91666 |
hex | 30ebf7d21 |
13132332321 has 4 divisors (see below), whose sum is σ = 17509776432. Its totient is φ = 8754888212.
The previous prime is 13132332259. The next prime is 13132332341. The reversal of 13132332321 is 12323323131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13132332321 - 211 = 13132330273 is a prime.
It is a super-3 number, since 3×131323323213 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13132332291 and 13132332300.
It is not an unprimeable number, because it can be changed into a prime (13132332341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188722051 + ... + 2188722056.
It is an arithmetic number, because the mean of its divisors is an integer number (4377444108).
Almost surely, 213132332321 is an apocalyptic number.
It is an amenable number.
13132332321 is a deficient number, since it is larger than the sum of its proper divisors (4377444111).
13132332321 is an equidigital number, since it uses as much as digits as its factorization.
13132332321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4377444110.
The product of its digits is 1944, while the sum is 24.
Adding to 13132332321 its reverse (12323323131), we get a palindrome (25455655452).
The spelling of 13132332321 in words is "thirteen billion, one hundred thirty-two million, three hundred thirty-two thousand, three hundred twenty-one".
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