Base | Representation |
---|---|
bin | 111101001001110000… |
… | …1110100011010101001 |
3 | 110112222012112021110212 |
4 | 1322103201310122221 |
5 | 4122422434310311 |
6 | 140155055550505 |
7 | 12326222505326 |
oct | 1722341643251 |
9 | 415865467425 |
10 | 131324135081 |
11 | 50770061447 |
12 | 2155022b435 |
13 | c4cb310109 |
14 | 64db2adb4d |
15 | 363921ec8b |
hex | 1e938746a9 |
131324135081 has 2 divisors, whose sum is σ = 131324135082. Its totient is φ = 131324135080.
The previous prime is 131324135011. The next prime is 131324135119. The reversal of 131324135081 is 180531423131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126846384025 + 4477751056 = 356155^2 + 66916^2 .
It is a cyclic number.
It is not a de Polignac number, because 131324135081 - 214 = 131324118697 is a prime.
It is a super-2 number, since 2×1313241350812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131324135011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65662067540 + 65662067541.
It is an arithmetic number, because the mean of its divisors is an integer number (65662067541).
Almost surely, 2131324135081 is an apocalyptic number.
It is an amenable number.
131324135081 is a deficient number, since it is larger than the sum of its proper divisors (1).
131324135081 is an equidigital number, since it uses as much as digits as its factorization.
131324135081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 32.
The spelling of 131324135081 in words is "one hundred thirty-one billion, three hundred twenty-four million, one hundred thirty-five thousand, eighty-one".
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