Base | Representation |
---|---|
bin | 10011000111000011011… |
… | …010001000010100110011 |
3 | 11122112201012012111221122 |
4 | 103013003122020110303 |
5 | 133004010304312433 |
6 | 2443143512212455 |
7 | 163610252665121 |
oct | 23070332102463 |
9 | 4575635174848 |
10 | 1313243432243 |
11 | 466a41754916 |
12 | 19262269a12b |
13 | 96ab8a4c292 |
14 | 477c03a0911 |
15 | 24261910198 |
hex | 131c3688533 |
1313243432243 has 2 divisors, whose sum is σ = 1313243432244. Its totient is φ = 1313243432242.
The previous prime is 1313243432227. The next prime is 1313243432257. The reversal of 1313243432243 is 3422343423131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313243432243 - 24 = 1313243432227 is a prime.
It is a super-2 number, since 2×13132434322432 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1313243435243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656621716121 + 656621716122.
It is an arithmetic number, because the mean of its divisors is an integer number (656621716122).
Almost surely, 21313243432243 is an apocalyptic number.
1313243432243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313243432243 is an equidigital number, since it uses as much as digits as its factorization.
1313243432243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 124416, while the sum is 35.
Adding to 1313243432243 its reverse (3422343423131), we get a palindrome (4735586855374).
The spelling of 1313243432243 in words is "one trillion, three hundred thirteen billion, two hundred forty-three million, four hundred thirty-two thousand, two hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •