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13132442403 = 325857249131
BaseRepresentation
bin11000011101100000…
…10010101100100011
31020220020000012021200
430032300102230203
5203343401124103
610011041452243
7643301630043
oct141660225443
936806005250
1013132442403
115629a15393
122666041083
1313139640a2
148c81a3723
1551cdb40a3
hex30ec12b23

13132442403 has 12 divisors (see below), whose sum is σ = 18972398328. Its totient is φ = 8753431680.

The previous prime is 13132442359. The next prime is 13132442429. The reversal of 13132442403 is 30424423131.

13132442403 is a `hidden beast` number, since 1 + 3 + 13 + 244 + 2 + 403 = 666.

It is not a de Polignac number, because 13132442403 - 26 = 13132442339 is a prime.

It is a super-2 number, since 2×131324424032 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13132442903) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 71853 + ... + 177278.

It is an arithmetic number, because the mean of its divisors is an integer number (1581033194).

Almost surely, 213132442403 is an apocalyptic number.

13132442403 is a deficient number, since it is larger than the sum of its proper divisors (5839955925).

13132442403 is a wasteful number, since it uses less digits than its factorization.

13132442403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 254994 (or 254991 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 13132442403 its reverse (30424423131), we get a palindrome (43556865534).

It can be divided in two parts, 13132 and 442403, that added together give a triangular number (455535 = T954).

The spelling of 13132442403 in words is "thirteen billion, one hundred thirty-two million, four hundred forty-two thousand, four hundred three".

Divisors: 1 3 9 5857 17571 52713 249131 747393 2242179 1459160267 4377480801 13132442403