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131324444417 is a prime number
BaseRepresentation
bin111101001001110001…
…0111111111100000001
3110112222020002222210202
41322103202333330001
54122423024210132
6140155110334545
712326225234225
oct1722342777401
9415866088722
10131324444417
11507702528a1
122155035a455
13c4cb3bab5a
1464db350785
153639281762
hex1e938bff01

131324444417 has 2 divisors, whose sum is σ = 131324444418. Its totient is φ = 131324444416.

The previous prime is 131324444401. The next prime is 131324444437. The reversal of 131324444417 is 714444423131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106099381441 + 25225062976 = 325729^2 + 158824^2 .

It is a cyclic number.

It is not a de Polignac number, because 131324444417 - 24 = 131324444401 is a prime.

It is a super-2 number, since 2×1313244444172 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131324444437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65662222208 + 65662222209.

It is an arithmetic number, because the mean of its divisors is an integer number (65662222209).

Almost surely, 2131324444417 is an apocalyptic number.

It is an amenable number.

131324444417 is a deficient number, since it is larger than the sum of its proper divisors (1).

131324444417 is an equidigital number, since it uses as much as digits as its factorization.

131324444417 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129024, while the sum is 38.

Adding to 131324444417 its reverse (714444423131), we get a palindrome (845768867548).

The spelling of 131324444417 in words is "one hundred thirty-one billion, three hundred twenty-four million, four hundred forty-four thousand, four hundred seventeen".