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1313262501257 = 7187608928751
BaseRepresentation
bin10011000111000100100…
…010110111110110001001
311122112202112002022201102
4103013010202313312021
5133004030200020012
62443145433031145
7163610604035660
oct23070442676611
94575675068642
101313262501257
11466a51499733
12192628b554b5
1396abc997a15
14477c2b25dd7
152426342a2c2
hex131c48b7d89

1313262501257 has 4 divisors (see below), whose sum is σ = 1500871430016. Its totient is φ = 1125653572500.

The previous prime is 1313262501223. The next prime is 1313262501263. The reversal of 1313262501257 is 7521052623131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313262501257 - 212 = 1313262497161 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1313262501257.

It is not an unprimeable number, because it can be changed into a prime (1313262401257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93804464369 + ... + 93804464382.

It is an arithmetic number, because the mean of its divisors is an integer number (375217857504).

Almost surely, 21313262501257 is an apocalyptic number.

It is an amenable number.

1313262501257 is a deficient number, since it is larger than the sum of its proper divisors (187608928759).

1313262501257 is an equidigital number, since it uses as much as digits as its factorization.

1313262501257 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187608928758.

The product of its (nonzero) digits is 75600, while the sum is 38.

The spelling of 1313262501257 in words is "one trillion, three hundred thirteen billion, two hundred sixty-two million, five hundred one thousand, two hundred fifty-seven".

Divisors: 1 7 187608928751 1313262501257