Base | Representation |
---|---|
bin | 1011111100011100010111… |
… | …0001100111011011110001 |
3 | 1201111111122122211100111221 |
4 | 2333013011301213123301 |
5 | 3210132422441021001 |
6 | 43533122050305041 |
7 | 2523554542554343 |
oct | 277070561473361 |
9 | 51444578740457 |
10 | 13133033142001 |
11 | 4203762916353 |
12 | 158132a288181 |
13 | 743594079616 |
14 | 3358dc283293 |
15 | 17b9489391a1 |
hex | bf1c5c676f1 |
13133033142001 has 2 divisors, whose sum is σ = 13133033142002. Its totient is φ = 13133033142000.
The previous prime is 13133033141993. The next prime is 13133033142007. The reversal of 13133033142001 is 10024133033131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11557443341376 + 1575589800625 = 3399624^2 + 1255225^2 .
It is a cyclic number.
It is not a de Polignac number, because 13133033142001 - 23 = 13133033141993 is a prime.
It is not a weakly prime, because it can be changed into another prime (13133033142007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566516571000 + 6566516571001.
It is an arithmetic number, because the mean of its divisors is an integer number (6566516571001).
Almost surely, 213133033142001 is an apocalyptic number.
It is an amenable number.
13133033142001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133033142001 is an equidigital number, since it uses as much as digits as its factorization.
13133033142001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13133033142001 its reverse (10024133033131), we get a palindrome (23157166175132).
The spelling of 13133033142001 in words is "thirteen trillion, one hundred thirty-three billion, thirty-three million, one hundred forty-two thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •