Base | Representation |
---|---|
bin | 1011111100011100101000… |
… | …0001111111011010101010 |
3 | 1201111111211122011220211021 |
4 | 2333013022001333122222 |
5 | 3210133044230342102 |
6 | 43533133120523054 |
7 | 2523556400505604 |
oct | 277071201773252 |
9 | 51444748156737 |
10 | 13133104543402 |
11 | 420379a154278 |
12 | 158134a18048a |
13 | 7435a5ab8c7c |
14 | 33590794c174 |
15 | 17b94ed40137 |
hex | bf1ca07f6aa |
13133104543402 has 4 divisors (see below), whose sum is σ = 19699656815106. Its totient is φ = 6566552271700.
The previous prime is 13133104543291. The next prime is 13133104543417. The reversal of 13133104543402 is 20434540133131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11564821702681 + 1568282840721 = 3400709^2 + 1252311^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283276135849 + ... + 3283276135852.
Almost surely, 213133104543402 is an apocalyptic number.
13133104543402 is a deficient number, since it is larger than the sum of its proper divisors (6566552271704).
13133104543402 is an equidigital number, since it uses as much as digits as its factorization.
13133104543402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6566552271703.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 13133104543402 its reverse (20434540133131), we get a palindrome (33567644676533).
The spelling of 13133104543402 in words is "thirteen trillion, one hundred thirty-three billion, one hundred four million, five hundred forty-three thousand, four hundred two".
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