Base | Representation |
---|---|
bin | 1011111100011100101001… |
… | …1011000000001001101001 |
3 | 1201111111212002112000210120 |
4 | 2333013022123000021221 |
5 | 3210133102420200014 |
6 | 43533133513233453 |
7 | 2523556510314225 |
oct | 277071233001151 |
9 | 51444762460716 |
10 | 13133111100009 |
11 | 42037a292235a |
12 | 1581350402889 |
13 | 7435a7273414 |
14 | 335908777785 |
15 | 17b9506d7ba9 |
hex | bf1ca6c0269 |
13133111100009 has 4 divisors (see below), whose sum is σ = 17510814800016. Its totient is φ = 8755407400004.
The previous prime is 13133111099993. The next prime is 13133111100023. The reversal of 13133111100009 is 90000111133131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13133111100009 - 24 = 13133111099993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13133111100049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188851849999 + ... + 2188851850004.
It is an arithmetic number, because the mean of its divisors is an integer number (4377703700004).
Almost surely, 213133111100009 is an apocalyptic number.
It is an amenable number.
13133111100009 is a deficient number, since it is larger than the sum of its proper divisors (4377703700007).
13133111100009 is an equidigital number, since it uses as much as digits as its factorization.
13133111100009 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4377703700006.
The product of its (nonzero) digits is 243, while the sum is 24.
The spelling of 13133111100009 in words is "thirteen trillion, one hundred thirty-three billion, one hundred eleven million, one hundred thousand, nine".
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