Base | Representation |
---|---|
bin | 11101110111000111101000… |
… | …110100101000001101111011 |
3 | 122020000010120122020110001121 |
4 | 131313013220310220031323 |
5 | 114203212114001320443 |
6 | 1143152403435130111 |
7 | 36443234416430611 |
oct | 3567075064501573 |
9 | 566003518213047 |
10 | 131331121120123 |
11 | 38934241093601 |
12 | 12890a268a3937 |
13 | 58386190ab5b2 |
14 | 2460662a2b6b1 |
15 | 102b3557514ed |
hex | 7771e8d2837b |
131331121120123 has 2 divisors, whose sum is σ = 131331121120124. Its totient is φ = 131331121120122.
The previous prime is 131331121120039. The next prime is 131331121120169. The reversal of 131331121120123 is 321021121133131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131331121120123 is a prime.
It is not a weakly prime, because it can be changed into another prime (131331121120523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65665560560061 + 65665560560062.
It is an arithmetic number, because the mean of its divisors is an integer number (65665560560062).
Almost surely, 2131331121120123 is an apocalyptic number.
131331121120123 is a deficient number, since it is larger than the sum of its proper divisors (1).
131331121120123 is an equidigital number, since it uses as much as digits as its factorization.
131331121120123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 131331121120123 its reverse (321021121133131), we get a palindrome (452352242253254).
The spelling of 131331121120123 in words is "one hundred thirty-one trillion, three hundred thirty-one billion, one hundred twenty-one million, one hundred twenty thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •