1313321211121 has 4 divisors (see below), whose sum is σ = 1343863564912. Its totient is φ = 1282778857332.

The previous prime is 1313321211119. The next prime is 1313321211127. The reversal of 1313321211121 is 1211121233131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313321211121 - 2¹ = 1313321211119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313321211092 and 1313321211101.

It is not an unprimeable number, because it can be changed into a prime (1313321211127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15271176831 + ... + 15271176916.

It is an arithmetic number, because the mean of its divisors is an integer number (335965891228).

Almost surely, 2^{1313321211121} is an apocalyptic number.

It is an amenable number.

1313321211121 is a deficient number, since it is larger than the sum of its proper divisors (30542353791).

1313321211121 is an equidigital number, since it uses as much as digits as its factorization.

1313321211121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30542353790.

The product of its digits is 216, while the sum is 22.

Adding to 1313321211121 its reverse (1211121233131), we get a palindrome (2524442444252).

The spelling of 1313321211121 in words is "one trillion, three hundred thirteen billion, three hundred twenty-one million, two hundred eleven thousand, one hundred twenty-one".