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131333221100153 is a prime number
BaseRepresentation
bin11101110111001001100101…
…111111011010101001111001
3122020000022222222201111002202
4131313021211333122221321
5114203230414100201103
61143153352053035545
736443340436112432
oct3567114577325171
9566008888644082
10131333221100153
1138935119508696
1212891312025bb5
135838892190327
1424607c18b0489
15102b429cb2988
hex777265fdaa79

131333221100153 has 2 divisors, whose sum is σ = 131333221100154. Its totient is φ = 131333221100152.

The previous prime is 131333221100111. The next prime is 131333221100183. The reversal of 131333221100153 is 351001122333131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109216545251584 + 22116675848569 = 10450672^2 + 4702837^2 .

It is a cyclic number.

It is not a de Polignac number, because 131333221100153 - 218 = 131333220838009 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (131333221100183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666610550076 + 65666610550077.

It is an arithmetic number, because the mean of its divisors is an integer number (65666610550077).

Almost surely, 2131333221100153 is an apocalyptic number.

It is an amenable number.

131333221100153 is a deficient number, since it is larger than the sum of its proper divisors (1).

131333221100153 is an equidigital number, since it uses as much as digits as its factorization.

131333221100153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4860, while the sum is 29.

Adding to 131333221100153 its reverse (351001122333131), we get a palindrome (482334343433284).

The spelling of 131333221100153 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, two hundred twenty-one million, one hundred thousand, one hundred fifty-three".