13133355503953 has 2 divisors, whose sum is σ = 13133355503954. Its totient is φ = 13133355503952.

The previous prime is 13133355503927. The next prime is 13133355504023. The reversal of 13133355503953 is 35930555333131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8113479405889 + 5019876098064 = 2848417^2 + 2240508^2 .

It is a cyclic number.

It is not a de Polignac number, because 13133355503953 - 2⁵ = 13133355503921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13133355503897 and 13133355503906.

It is not a weakly prime, because it can be changed into another prime (13133355503453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566677751976 + 6566677751977.

It is an arithmetic number, because the mean of its divisors is an integer number (6566677751977).

Almost surely, 2^{13133355503953} is an apocalyptic number.

It is an amenable number.

13133355503953 is a deficient number, since it is larger than the sum of its proper divisors (1).

13133355503953 is an equidigital number, since it uses as much as digits as its factorization.

13133355503953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4100625, while the sum is 49.

The spelling of 13133355503953 in words is "thirteen trillion, one hundred thirty-three billion, three hundred fifty-five million, five hundred three thousand, nine hundred fifty-three".