Base | Representation |
---|---|
bin | 1011111100011101101111… |
… | …1110001111101100101100 |
3 | 1201111112121121120201011210 |
4 | 2333013123332033230230 |
5 | 3210134203310121104 |
6 | 43533223032314420 |
7 | 2523600014154135 |
oct | 277073376175454 |
9 | 51445547521153 |
10 | 13133405551404 |
11 | 4203934057016 |
12 | 1581412b42a10 |
13 | 74362327a808 |
14 | 335935904c8c |
15 | 17b96b49c989 |
hex | bf1dbf8fb2c |
13133405551404 has 24 divisors (see below), whose sum is σ = 30645274966768. Its totient is φ = 4377707277120.
The previous prime is 13133405551391. The next prime is 13133405551481. The reversal of 13133405551404 is 40415550433131.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11241907 + ... + 12355050.
Almost surely, 213133405551404 is an apocalyptic number.
It is an amenable number.
13133405551404 is an abundant number, since it is smaller than the sum of its proper divisors (17511869415364).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13133405551404 is a wasteful number, since it uses less digits than its factorization.
13133405551404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23643345 (or 23643343 counting only the distinct ones).
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 13133405551404 its reverse (40415550433131), we get a palindrome (53548955984535).
The spelling of 13133405551404 in words is "thirteen trillion, one hundred thirty-three billion, four hundred five million, five hundred fifty-one thousand, four hundred four".
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