1313401111931 has 4 divisors (see below), whose sum is σ = 1313568368112. Its totient is φ = 1313233855752.

The previous prime is 1313401111889. The next prime is 1313401111943. The reversal of 1313401111931 is 1391111043131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313401111931 - 2²² = 1313396917627 is a prime.

It is a super-3 number, since 3×1313401111931³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313401111894 and 1313401111903.

It is not an unprimeable number, because it can be changed into a prime (1313401111951) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 83616311 + ... + 83632016.

It is an arithmetic number, because the mean of its divisors is an integer number (328392092028).

Almost surely, 2^{1313401111931} is an apocalyptic number.

1313401111931 is a deficient number, since it is larger than the sum of its proper divisors (167256181).

1313401111931 is an equidigital number, since it uses as much as digits as its factorization.

1313401111931 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 167256180.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 1313401111931 in words is "one trillion, three hundred thirteen billion, four hundred one million, one hundred eleven thousand, nine hundred thirty-one".