1313401161497 has 2 divisors, whose sum is σ = 1313401161498. Its totient is φ = 1313401161496.

The previous prime is 1313401161421. The next prime is 1313401161517. The reversal of 1313401161497 is 7941611043131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1296628580416 + 16772581081 = 1138696^2 + 129509^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313401161497 - 2¹⁸ = 1313400899353 is a prime.

It is a super-2 number, since 2×1313401161497² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1313401161407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656700580748 + 656700580749.

It is an arithmetic number, because the mean of its divisors is an integer number (656700580749).

Almost surely, 2^{1313401161497} is an apocalyptic number.

It is an amenable number.

1313401161497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313401161497 is an equidigital number, since it uses as much as digits as its factorization.

1313401161497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 41.

The spelling of 1313401161497 in words is "one trillion, three hundred thirteen billion, four hundred one million, one hundred sixty-one thousand, four hundred ninety-seven".