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1313402012031 = 34492185144623
BaseRepresentation
bin10011000111001100110…
…111000100000101111111
311122120010020121012112010
4103013030313010011333
5133004321403341111
62443211335142303
7163614216620634
oct23071467040577
94576106535463
101313402012031
1146701321719a
12192667814993
1396b12863485
14477d748018b
15242707d6aa6
hex131ccdc417f

1313402012031 has 16 divisors (see below), whose sum is σ = 1755222566400. Its totient is φ = 873591667200.

The previous prime is 1313402012003. The next prime is 1313402012063. The reversal of 1313402012031 is 1302102043131.

It is not a de Polignac number, because 1313402012031 - 218 = 1313401749887 is a prime.

It is a super-2 number, since 2×13134020120312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1313402011989 and 1313402012007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313402012231) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29410986 + ... + 29455608.

It is an arithmetic number, because the mean of its divisors is an integer number (109701410400).

Almost surely, 21313402012031 is an apocalyptic number.

1313402012031 is a deficient number, since it is larger than the sum of its proper divisors (441820554369).

1313402012031 is a wasteful number, since it uses less digits than its factorization.

1313402012031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66926.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1313402012031 its reverse (1302102043131), we get a palindrome (2615504055162).

The spelling of 1313402012031 in words is "one trillion, three hundred thirteen billion, four hundred two million, twelve thousand, thirty-one".

Divisors: 1 3 449 1347 21851 44623 65553 133869 9811099 20035727 29433297 60107181 975057173 2925171519 437800670677 1313402012031